Study guides

Q: What is 3 5 2 5?

Write your answer...

Submit

Related questions

There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .

3 ÷ 2/5 = 3/1 ÷ 2/5 = 3/1 × 5/2 = (3×5)/(1×2) = 15/2 = 7½

1 2/3=5/3 (2/3)/(5/3)=(2/3)*(3/5)=2/5

5/3

450 = 2*3*3*5*5450 = 2*3*3*5*5450 = 2*3*3*5*5450 = 2*3*3*5*5

There are too many to list. Some examples:2+2+2+2+...+2 (35 lots of them). 7+7+7+7+7+7+7+7+7+7 2+2+2+2+2+2+2+2+2+2+3+3+3+3+3+3+3+3+3+3+5+5+5+5+5+5+5+5+5+5

Please help me

-2

41.The prime numbers which are less than 25 are 2, 3, 5, 7, 11, 13, 17, 19 and 23.2 + 23 Using two numbers3 + 3 + 19 Using three numbers3 + 5 + 173 + 11 + 115 + 7 + 137 + 7 + 112 + 2 + 2 + 19 Using four numbers2 + 3 + 3 + 172 + 3 + 7 + 132 + 5 + 5 + 132 + 5 + 7 + 112 + 2 + 2 + 2 + 17 Using five numbers2 + 2 + 3 + 5 + 132 + 2 + 3 + 7 + 112 + 2 + 5 + 5 + 112 + 2 + 7 + 7 + 73 + 3 + 3 + 3 + 133 + 3 + 3 + 5 + 113 + 3 + 5 + 7 + 73 + 5 + 5 + 5 + 75 + 5 + 5 + 5 + 52 + 2 + 2 + 3 + 3 + 13 Using six numbers2 + 2 + 2 + 3 + 5 + 112 + 2 + 2 + 5 + 7 + 72 + 3 + 3 + 3 + 3 + 112 + 3 + 3 + 3 + 7 + 72 + 3 + 3 + 5 + 5 + 72 + 3 + 5 + 5 + 5 + 53 + 3 + 3 + 3 + 3 + 5 + 5 Using seven numbers2 + 2 + 2 + 2 + 2 + 2 + 2 + 11 Using eight numbers2 + 2 + 2 + 3 + 3 + 3 + 3 + 72 + 3 + 3 + 3 + 3 + 3 + 3 + 52 + 2 + 2 + 2 + 2 + 2 + 3 + 3 + 7 Using nine numbers2 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 52 + 2 + 3 + 3 + 3 + 3 + 3 + 3 + 32 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 7 Using ten numbers2 + 2 + 2 + 2 + 2 + 2 + 2 + 3 + 3 + 52 + 2 + 2 + 2 + 2 + 3 + 3 + 3 + 3 + 32 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 5 Using eleven numbers2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 3 + 3 + 32 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 3 Using twelve numbers

3-5, 2-5, 3-5, 2-2, 5-2, 5-2, 3-3, 4-3, 4-4,

1/[5 + 3*sqrt(2)] = [5 - 3*sqrt(2)]/{[5 + 3*sqrt(2)][5 - 3*sqrt(2)]} = [5 + 3*sqrt(2)]/[25 - 18] = [5 - 3*sqrt(2)]/7

5*(3-4/2) = 5*(3-2) = 5*1 = 5

Answer: No Explanation: Product of 2/3 and 5 = (2/3)×(5) = (2×5)/3 = 10/3 = 3.333..... So, 3.3333...... is less than 5. Hence, Product of 2/3 and 5 is less than 5.

3 3 5 3 2 3 1 5 5 6 5 4 5 2 8 7 6 5 4 3 2 5 3 2 3 1

3/2 ÷ 3/5 = 3/2 x 5/3 = 5/2 = 21/2

7+2+2 or 5+3+37+2+2 or 5+3+37+2+2 or 5+3+37+2+2 or 5+3+3

1800

factoring 60=2*2*3*5 100=2*2*5*5 180=2*2*3*3*5 450=2*3*3*5*5 LCM=2*2*3*3*5*5=900

270,000 has a prime factorization of: 2*2*2*2*3*3*3*5*5*5*5

-2 √5 + 3 √5 = (-2 + 3) √5 = 1 √5 = √5

180 = 2*2*3*3*5180 = 2*2*3*3*5180 = 2*2*3*3*5180 = 2*2*3*3*5

The prime factorization of 375 is = 3 * 5 * 5 * 5 = 3 * 5^3 The prime factorization of 1000 is 2 * 2 * 2 * 5 * 5 * 5 = 2^3 * 5^3

6/5 + 4/5 = 10/5 = 2 * * * * * No. 3 and 3 over 5 is 33/5, not (3+3)/5 So, the required sum is 33/5 + 22/5 = 3 + 2 + 3/5 + 2/5 = 5 + 5/5 = 6

27,000 = 2*2*2*3*3*3*5*5*5

.5